What integer value of n will satisfy n + 10 > 11 and -4n

What is the solution to j + (-3) = 9?

Stels [109]

Answer:

j = 12

Step-by-step explanation:

j + (-3) = 9

j = 12

8 0

3 years ago

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numb

vlabodo [156]

To withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

As given in the question,

Using automated teller machine customers at the bank withdraw money

Numeric pattern given for the personal ID numbers is

2, 13, 24, 35

First term 'a'= 2

Common difference between consecutive terms are same

'd'=13 -2

=11

It is an arithmetic progression series

nth term = a+ (n-1)d

5th term = 2 +(5-1)11

=46

6th term =2+(6 -1)11

=57

7th term= 2+ (7-1)11

= 68

Therefore, to withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

The complete question is:

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numbers by completing the numeric patterns. 2, 13, 24, 35, ___, ___, ____.

Learn more about pattern here

brainly.com/question/14720576

#SPJ1

7 0

1 year ago

Caleb and two friends are sharing a half quart of milk equally what fraction of a quart of milk does each other friend get

AveGali [126]

To find out what fraction of the half quart each friend will get, divide the 1/2 quart into 2 groups.

1/2 divided by 2 is the same as 1/2 x 1/2 or 1/4 quart.

Each friend will get 1/4 quart of milk.

5 0

3 years ago

What is the reciprocal of 9/7?

Bingel [31]

Answer:

its 7/9

Step-by-step explanation:

you just have to flip the fractions

6 0

2 years ago

Read 2 more answers

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

What integer value of n will satisfy n + 10 > 11 and -4n > -12?