Step-by-step explanation:
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Solve z2 – 2z – 35 = 0 using the zero product property.
1 answer:
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Complete the square for x and y.
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
Answer:
Step-by-step explanation:
The point is located in Quadrant II of the graph, where x-values are negative and y-values are positive.
Each marking on the graph represents one unit of distance. The two <em>axes</em> meet at the origin, where the coordinate point is equal to .
So, you can count backwards once from the origin to get your x-value ⇒ and count up upwards four times from
to get your y-value ⇒
.
Finally, place these in a coordinate point ⇒
.