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Nikolay [14]
3 years ago
15

9. People should not drink sea water. How does drinking sea water affect the cells in the

Biology
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

I believe it is A

Explanation:

Hope this is correct! :>

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During meiosis homologous Chromosomes can exchange DNA in a process known as
Kisachek [45]

Answer:

crossing over

Explanation:

Crossing over is where homologs can exchange DNA which leads to genetic variation

3 0
3 years ago
Calcium iron vitamin c and vitamin d in which of these is organic substances​
Elodia [21]

Answer:

vitamin C and vitamin d

Explanation:

because if the digested first only no vitamin it's supply to our body

examples like eggs

8 0
2 years ago
Which characteristic sets hominins apart from other primates?
grigory [225]
Bipedalism is the characteristic that hominins have and sets them apart from other primates. Bipedalism refers to locomoting. It is walking primarily upright on two feet, movement on two feet.
Walking upright distinguishes humans from other primates. Walking<span>, </span>running<span>, or </span>hopping are types of bipedal movement.
5 0
3 years ago
The arrangement of organisms into orderly groups based on their similarities is called
USPshnik [31]

Answer: Classification\

Explanation:

Classification is the arrangement of organisms into orderly groups based on their similarities. In order to classify an organism, a biologist must use a system that groups organisms according to shared characteristics and their relationships between one another.

7 0
4 years ago
While alive, an organism absorbs (radioactive) carbon 14 at such a rate that the proportion of carbon 14 in the organism remains
Inga [223]

Answer:

The person has been dead for approximately 15,300 years

Explanation:

<u>Available data</u>:

  • The half-life of carbon 14 is 5,600 years
  • The human skeleton level of carbon 14 is 15% that of a living human

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body at time 0 = 100%
  • C14T₁ ⇒ Amount of carbon in the dead body at time 1 = 15%
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5600 years
  • T₀ = 0
  • T₁ = ???

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5600

λ = 0.000123

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (15%/100%) = Ln 0.15 = - 1.89

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 1.89 = - 0.000123 x T₁

T₁ = - 1.89 / - 0.000123

T₁ = 15,365 years

The person has been dead for approximately 15,300 years

4 0
3 years ago
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