The answer is 864, its so easy
X^2+7x-30
what we do is we find what 2 number multiply to get -30 and add to get 7
factor 30
30=2 times 3 times 5
we know that is has to be negative eventually so one is negative and one is positivie so we do2 factors and add
2 times 5=10
10 and -3
add
10-3=7
checks
10 times -3=-30
so we put those in
(x-3)(x+10)
factored
Answer:
-2.1
Step-by-step explanation:
We have an equation and the question is asking us to look for x.
To solve, we must isolate x and get it on its own.
2.5(x + 4) = 4.75
Distribute the 2.5 to get rid of the parenthesis :
(2.5(x) + 4(2.5)) = 4.75
2.5x + 10 = 4.75
Subtract ten from both sides :
2.5x = -5.25
Divide 2.5 by both sides to get x alone :
x = -2.1
Answer:
x = ![\sqrt{87}](https://tex.z-dn.net/?f=%5Csqrt%7B87%7D)
Step-by-step explanation:
if you draw a perpendicular segment from the vertex between sides 5 and 16 to the opposite side then you have a right triangle and can use the Pythagorean Theorem, a² + b² = c²
a = x
b = 13 (you get this from 18 - 5)
c = 16
x² + 13² = 16²
x² + 169 = 256
x² = 87
x = √87
Answer:
The price of
1 adult ticket = $15
1 student ticket = $9
Step-by-step explanation:
Let
The price of adult tickets be represented by a
The price of student tickets be represented by s
Therefore:
On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.
4a + 10s = $150.... Equation 1
The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.
a + 10s = $105.... Equation 2
a = $105 - 10s
Therefore, we substitute : $105 - 10s = a in Equation 1
4a + 10s = $150.... Equation 1
4($105 - 10s) + 10s = $150
$420 - 40s + 10s = $150
Collect like terms
- 40s + 10s = $150 - $420
-30s = -$270
Divide both sides by -30
-30s/-30 = -$270/-30
s = $9
We find a
a = $105 - 10s
a = $105 - 10($9)
a = $105 - $90
a = $15
Therefore, the price of
1 adult ticket = $15
1 student ticket = $9