Answer:
(a) The molality of this solution is 0.0613
(b)The molality of this solution is 2.04
Explanation:
The molality (m) of a solution is defined as the number of moles of solute present per kg of solvent.
The Molality of a solution is determined by the expression:
Molality is expressed in units
(a) You have 14.3 g of sucrose (C₁₂H₂₂O₁₁), the solute. With the molar mass of sucrose being 342 , then 14.3 grams of the compound represents the following number of moles:
0.042 moles
Having 685 g= 0.685 kg (being 1000 g= 1 kg) of water, the solvent, molality can be calculated as:
Solving:
molality= 0.0613
<u><em>The molality of this solution is 0.0613</em></u><u><em></em></u>
(b) In this case you have 7.15 moles of ethylene glycol (C₂H₆O₂), the solute, in 3505 g (equal to 3.505 kg) of water, the solvent, molality can be calculated as:
Solving:
molality= 2.04
<em><u>The molality of this solution is 2.04</u></em><em><u /></em>