Answer:
THE EMPIRICAL FORMULA FOR THE PURE HYDROCARBON IS CH4
Explanation:
A pure hydrocarbon contains carbon and hydrogen
Percentage composition of carbon = 74.5 %
Percentage composition of hydrogen = 25.5
In order to calculate the empirical formula of this hydrocarbon, you follow these couple of steps.
write out the percentage composition and divide by the relative atomic mass of the respective constituents.
Carbon = 74.5 / 12 = 6.2083
Hydrogen = 25.5 / 1 = 25.5
Next is to divide the values by the lowest factor
Carbon = 6.2083 / 6.2083 = 1
Hydrogen = 25.5 / 6.2083 = 4.1
Next is to write the empirical formula:
C H4
In conclusion the empirical formula for the pure hydrcarbon is CH4
The answer would be: <span>a.a mixture that is uniform throughout
A homogenous mixture would be hardly distinguishable since the solute spread evenly inside the solvent. A heterogeneous mixture is not spread evenly so it is </span>easily distinguishable.A suspension has a big molecule solute that will slowly settle and make sediment at the base of the solution. A colloid mixture is suspended but it won't settle like suspension does.
Hi!!
<em>CORRECT ANSWER = D</em>
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Heat vaporization is
D- It's the heat required to change a gram of substance from a<em> </em><em><u>liquid to a gas</u></em>
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☺☺☺
Answer:
4
Step-by-step explanation:
The reactions are:
Glycolysis: 1 glucose ⟶ 2 pyruvate
Link reaction: 2 × [1 pyruvate ⟶ 1 acetyl CoA]
Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]
Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,
1 glucose ⟶ <u>2 pyruvate
</u>
<u>2 pyruvate</u> ⟶ <u>2 acetyl CoA
</u>
<u>2 AcetylCoA </u>⟶ 4 CO₂
<em>Overall</em> : 1 glucose ⟶ 4 CO₂
For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.