It would actually rise.
-11 + 4 = 6
-11 -10 -9 -8 -7 -6 -4 -3 -2 -1 0
l -------------------> l
it rose 6 degrees (or dropped -6 degrees, to match the question) :)
Answer:
Distance D = √ [(2 - x)^2 + (3 - 4x^3)^2].
Step-by-step explanation:
Use the distance formula:
D = √[(x2 - x1)^2 + (y2 - y1)^2].
So here it is
D = √[(2 - x)^2 + (4 - y)^2] where x,y is any point on the curve.
D = √[2 - x)^2 + (4 - (4x^3 + 1))^2]
D = √ [(2 - x)^2 + (3 - 4x^3)^2]
Replace y with 0 and solve for x.
x= -1.52138
Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
