G(x)=√8x <br> What is the domain of g?

Chad is eating a 50-gram chocolate bar which contains 30% cocoa. How many grams of cocoa are in the chocolate bar?

Allushta [10]

Answer: 15 grams

If he had 100 grams of candy bar, then 30% of that is 30 grams (since 30/100 = 30%). Cut this in half and we end up with 30/2 = 15.

Another way to find the answer is to multiply 50 and 0.30 which is the decimal form of 30%. So we have 50*0.30 = 15 which is the same answer.

8 0

3 years ago

What does x and y equal

GaryK [48]

Answer:

x=5, y=-3

Step-by-step explanation:

we can find the answer by plugging in x=3y+14 to the second equation

5(3y+14)-2y=31

simplify

15y+70-2y=31

13y=-39

y=-3

now, plug in this to the initial equation x=3y+14

x=3(-3)+14

x=-9+14

x=5

6 0

2 years ago

Read 2 more answers

Pls help! 5,6,7<br> 30 points

Deffense [45]

Jon=x-2 jor=x

2(x-2)=x+6

2x-4=x+6

combine like terms

x=10 Jordan's age

x-2 or 10-2 =8 Jonathan's age

13-10= 3 years apart

when aylon was 3 Karina was 6

2×3 =6

this was 7 years ago(answer)

10-3=7

13-6=7

48-36=12 years apart

when kd was 6 and md 18

3×6=18

30 years ago

36-6=30

48-18=30

3 0

3 years ago

surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo

balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be: