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2 years ago

Help me please!!!!!!!!

Mathematics

1 answer:

kompoz [17]2 years ago

3 0

Answer:

The answer is A

Mean: 2

Median: 1

Step-by-step explanation:

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3-6n+3n=-3+4-4n can somebody help me?

ElenaW [278]

Anwser : n = -2
Combine Like Terms
Add 4n to both sides
Subtract 3 from both sides
A = n= -2

8 0

2 years ago

vladimir1956 [14]

Answer:

Inequality: 0.08x + 2300 ≥ 2800

Liz needs to sell products of $6250 at least.

Step-by-step explanation:

Given that:

Per month salary of Liz = $2300

Commission = 8% = $\frac{8}{100}}$ = 0.08

Amount Liz wants to earn = $2800

Let,

x be the amount of sales.

0.08x + 2300 ≥ 2800

0.08x ≥ 2800 - 2300

0.08x ≥ 500

Dividing both sides by 0.08

$\frac{0.08x}{0.08}\geq \frac{500}{0.08}\\x\geq 6250$

Hence,

Liz needs to sell products of $6250 at least.

5 0

2 years ago

Zak and Ryan earn $60 per week for delivering pizzas. Zak worked for x weeks and earned an additional total bonus of $25. Ryan w

Inessa05 [86]

Answer:

60x + 25 + 60y

Step-by-step explanation:

60 times x plus 60 times y plus 25

4 0

3 years ago

Read 2 more answers

Math 3×219solve using place value blocks

Maksim231197 [3]

3 times 219 is 657 so you need 6 hundred value blocks 5 ten value blocks and 7 one value blocks

8 0

2 years ago

Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3

Anastaziya [24]

Answer:

See explanation

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]$

$B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]$

A. Find AB:

$AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]$

B. Find BA:

$BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]$

C. Answers are not the same

D. Matrices multiplication is not commutastive in general, so

$AB\neq BA$

7 0

3 years ago