To find the point that divides the segment into a 2:3 partition, a formula can be used. The formula is:
[ x1 + (ratio)*(x2 - x1) , y1 + (ratio)*(y2 - y1) ]
Substituting the given values:
[ -3 + (2/5)*(3 + 3) , 1 + (2/5)*(5 - 1) <span>]
</span>(-0.6 , 2.6)
Therefore, the point P that divides segment AB into a 2:3 ratio is found at (-0.6 , 2.6).
Answer:
y=3x+10
Step-by-step explanation:
2=-12+b
b=10
Answer:
Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.
Step-by-step explanation:
Answer:
2 x 25 (50)
3 x 25 (75)
Step-by-step explanation:
