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Lapatulllka [165]
2 years ago
13

Suppose a company wants to structure its assets and liabilities such that its equity is unaffected by interest rate risk. To acc

omplish that objective, which of the following must the company do?
a. The duration of its liabilities must be longer than the duration of its assets.
b. The duration of its liabilities must equal the duration of its assets.
c. The duration of its liabilities must be shorter than the duration of its assets.
Business
1 answer:
Andreas93 [3]2 years ago
7 0

Answer: b. The duration of its liabilities must equal the duration of its assets

Explanation:

Since the company wants to structure its assets and liabilities such that its equity is unaffected by interest rate risk, then the duration of its liabilities must equal the duration of its assets.

It should be noted that when the duration of its liabilities is shorter than the duration of its assets, the duration gap is positive and when there's a rise in interest rate, the worth of assets will be affected more.

When duration of its liabilities is longer than the duration of its assets, the duration gap is negative and when there's a rise in interest rate, the worth of liabilities will be affected more.

Finally, when the duration of its liabilities is equal the duration of its assets, its equity is unaffected by interest rate risk.

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Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.

<u>Explanation:</u>

The problem is that of Multiple-server Queuing Model.

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Arrival rate, \lambda= 6 boats per hour.

Service rate, \mu= 10 boats per hour.

Probability of zero boats in the system,\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\} = 0.5385

<u>Average number of boats waiting in line for service:</u>

Lq =[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0

= [\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385 = 0.0593 boats.

The average time a boat will spend waiting for service, Wq  =  0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.

The average time a boat will spend at the dock, W =  0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.

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When a third party knows that an agent is acting on behalf of a principal, but does not know the identity of the principal, the
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Masteriza [31]
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valkas [14]

Answer:

3.44%

Explanation:

The computation of the return if sold the fund at the year end is shown below:

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