In the figure, we can consider that the base is the side that mesures 12 in and that the height is the side that measures 15 in, since that sides are perpendicular. So, we just need to use the given formula:

Hence, the area of the triangle is 90 in² (B).
Answer:
(x + 2)(4x - 2).
Step-by-step explanation:
(x+2)(2x+1)+(x+2)(2x-3)
Note that (x + 2) is common to 2 parts of the expression. So we have:
(x + 2)(2x + 1 + 2x - 3)
= Ix + 2)(4x - 2)
A. Factor the numerator as a difference of squares:

c. As

, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling


In particular,


so we have

For

and

, we can simplify the first term:

So our limit becomes
Answer:
man that's hard good luck