When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.
If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.
Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so .
Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so .
Subtract from the first equation the second equation:.
Similarly you can prove that .
PLS HELP ILL GIVE BRAINLIEST What are the coordinates of the center of the ellipse?
1 answer:
Answer:
Step-by-step explanation:
Standard equation of an ellipse,
(h, k) is the center of the ellipse
Value of a = Distance of the center from the vertex
b = Distance of the center from the covertex
From the picture attached,
a = Distance of the center (h, k) from the vertex (2, -2) = 3 units
b = Distance of the center (h, k) from the co-vertex (-1, 0) = 1 unit
Center of the ellipse (h, k) = (-1, -2)
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Answer:
To graph (like the provided picture) you must understand y=mx+b. Your m would stand for your slope which you need to determine with rise over run. Rise over run can be done by finding a place where both the x and y values are lined up. (0,-2) can be used as an example from the picture. You then want to find the next point where the x and y values line up which (-2,1) can be used. Go up 3 units and go to the LEFT 2 times which makes this a negative run. The slope would then be represented as -3/2.
Your x value stands for your x-value moving up or down while you b value stands for your y-intercept which point (0,-2) is represented as. Y represents the y value after the equation is plugged in with x and solved.
