Answer:
1.64
Step-by-step explanation:
The answer to the problem above is True. Standard form of an equation means the right side of the equation should be 0, and everything on the left side. For example, x^2 = 4 , to make this this in standard form you have to transfer number 4 to the left side of the equation making it x^2 - 4 = 0.
In this situation, if you will be asked to look for x, there is no need to make the equation in standard form, you can directly take the square root of both sides of the equation to get x.
Answer:
option A
Step-by-step explanation:
given,
sample of tritium, ³H
contents present of ³H = 5.25 mol
content of ³He = 6.35 mol
reaction
A₀ is the initial concentration
At is the concentration after time t
A₀ = 5.25 + 6.35 = 11.6 mol
At = 5.25
now,
k = 0.0563 /year
t = 14.1 yr
hence, the correct answer is option A
If you had absolutely no idea, then you'd have roughly two choices
of how to find it:
#1). Try numbers until you find the right one.
Pick a number.
Cube it.
If you get less than 729, go back and try a bigger number.
If you get more than 729, go back and try a smaller number.
Eventually you find the right one.
Try 1. 1³ = 1 . Too small.
Try 2. 2³ = 8 . Still too small.
Try 5. 5³ = 125 . Still too small.
Try 20. 20³ = 8,000. Ooops. Too big.
Try 10. 10³ = 1,000 Too big.
Try 8. 8³ = 512. Oooo. Too small, but maybe getting close.
Try 8.5. 8.5³ = 614.125 Still too small, but very close.
Try 9. 9³ = 729 . That's it ! yay !
#2). x³ = 729
Take the log of each side: log(x³) = log(729)
3 log(x) = log(729)
Divide each side by 3 : log (x) = (1/3) log(729)
Look up log(729) : log(x) = (1/3) (2.86272...)
= 0.95424...
Raise 10 to the power
of each side: 10^log(x) = 10⁰·⁹⁵⁴²⁴···
x = 8.99994...
(That's the way it is with logs.
They never come out even.)
