Answer:
In simplest form, it should be:
3:2
6 / 2 = 3
4 / 2 = 2
Hope this helps!
-3: y = -2 * (-3) - 7 = 6 - 7 = -1
0: y = -2 * 0 - 7 = -7
3: y = -2 * 3 - 7 = -6 - 7 = -13
6: y = -2 * 6 - 7 = -12 - 7 = =-19
Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
Answer is -10
Work: -(5+5)
12z^2 - 7z -12/ 3z^2 + 2z - 8
= (4z+3) (3z -4)/ (z+2)(3z -4)
= (4z + 3) / (x+2)
Hope this helps
