Answer:
![\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Ctext%7Btherefore%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D)
Answer:
An isosceles right triangle has 2 congruent sides.
6 pairs of shorts, for a
"s" dollars. A blazer costs 3 times as much, she bought one. The total was 139.50
6s + 3(6s) = 139.50
6s + 18s = 139.50
25s = 139.50 Divide everything by 25,
s = 5.58, which is how much the shorts were. Now for the blazers ;
It said they were three times the cost of shorts, if shorts are 5.58, it is 3*5.58.
3s
3(5.58)
16.74
The blazer cost 16.74
The total amount is the sum of the cost of three nights in the hotel, $346.86, the flight costs, $45.70 + $32.49 = $78.19, and four days of food, $60, the amount he lost, $25, less the amount he won, $75. Calculating,
($346.86 + $78.19 + $60 + $25) - ($75) = $435.05
