9x^2-16y^2=
(3x+4y)(3x-4y)
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>
Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>
Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>
The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
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<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.
It should take approximately 27 days using the water at an average of. 450 gallons per day
0.41567 is:
... rational because it can be expressed as a fraction (e.g., 41567/100000)
... not irrational for the same reason
... not whole (obviously)
... not integer (obviously)
Answer:
21
Step-by-step explanation:
Three raise to third power can be written as
. In this three is the base which is raised to third power.

Next we need to subtract 6 from Three raise to third power(i.e from 27)
which can be written mathematically as

Hence 6 less than three raised to the third power is 21 as explained above.