May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
This is a fair assumption, but not true in every instance. Since home runs do not indicate how many runs score, which are the decider in a win or a loss, they are less accurate at predicting.
Answer:
If x + 1 is odd, then x is even.
Step-by-step explanation:
The converse of the statement ...
if P, then Q.
is ...
if Q, then P.
Here, we have P="x is even" and Q="x+1 is odd". The converse statement is ...
if x+1 is odd, then x is even.
Step-by-step explanation:
x²+4-4x+y²=3
x²+y²-4x+1=0
In one revolution of the wheel, a point on the edge travels a distance equal to the circumference of the wheel.
The wheel has radius 1 ft, so its circumference is 2π (1 ft) = 2π ft.
Then the point has a linear speed of
(1/4 rev/s) * (2π ft/rev) = 2π/4 ft/s = π/2 ft/s