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2 years ago

Reasoning: Write a function g(x) to represent the translated graph. f(x) = 3x + 7 translated 4 units up.

Mathematics

2 answers:

Zanzabum2 years ago

5 0

Answer:

ajkskakakna

Step-by-step explanation:

babcdsjj no te preocupes por qué no me deja

dangina [55]2 years ago

5 0

Answer:

I am pretty sure its g(x) = 3x + 11

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You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first

Tomtit [17]

Answer:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

$Y \sim Binom(n=5, p=0.05)$

The probability mass function for the Binomial distribution is given as:

$P(Y)=(nCy)(p)^y (1-p)^{n-y}$

Where (nCx) means combinatory and it's given by this formula:

$nCy=\frac{n!}{(n-y)! y!}$

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0

3 years ago

Hi! I was wondering if you could help with this question please :)

Makovka662 [10]

Answer:

$R=\frac{QJ}{I^2t}$

Step-by-step explanation:

So we have the equation:

$Q=\frac{I^2Rt}{J}$

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

$(J)Q=(J)\frac{I^2Rt}{J}$

Simplify the right:

$JQ=I^2Rt$

We can rewrite our equation as:

$JQ=R(I^2t)$

So, to isolate the R variable, divide both sides by I²t:

$\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}$

The right side cancels, so:

$R=\frac{QJ}{I^2t}$

And we are done!

7 0

3 years ago

How does f(x) = 3* change over the interval x = 4 to x = 57

Vilka [71]

f(x) increase by a factor of 3

Explanation:

Given that f(x)= 3* and the interval is x=4 to x=57

Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.

Because the x is multiplied with 3 i.e., 3*

So f(x) increase by a factor of 3.

If we put x=4, then f(x)= 12 (∵ 3×4=12)

If we put x=5, the f(x)= 15 (∵ 3×5=15)

If we put x=6,the f(x)= 18 (∵ 3×6=18)

similarly., values of x= 7,8,9,...155.

Then,

If we put x=56, the f(x)=168

This process will continue until f(x)=171 for x=57.

6 0

3 years ago

7+3z-8-3z plz answer quick i have 10 points

Naddik [55]

-1+z because 7-8 would be -1 and positive 3-3 would just be the variable after

4 0

2 years ago

What is the range of the function graphed below?<br> ABCD

AlexFokin [52]

Answer:

(-4 , 0] ∪ (2, ∞)

Last option

Step-by-step explanation:

Since range is included 2 so (2, ∞) and other line is not included 0 but included -4 so it should be (-4, 0]

So range would be:

(-4 , 0] ∪ (2, ∞)

8 0

3 years ago