Taylor series is 
To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have
f(x) = ln(x)
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Since we need to have it centered at 9, we must take the value of f(9), and so on.
f(9) = ln(9)
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Following the pattern, we can see that for 
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This applies for n ≥ 1, Expressing f(x) in summation, we have
Combining ln2 with the rest of series, we have
Taylor series is
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Answer: 50
Step-by-step explanation:
exterior angles are supplement of interior angle therefore the 110 thing must be 70, also youre given 60 so 70+60=130
50 is missing from 180
I believe it's Line y=-x+2 and y=3x+1 intersect the y-axis. From what I've gathered, they are parallel lines, and both are set on the y-axis.
When we say right triangle, it is a triangle that has at least one angle equal to 90 degrees. In addition, an isosceles triangle can also be considered a right triangle given that it has two sides that are equal. In the given measurements above, the set is not considered as measurements of a right triangle. Therefore, the answer is FALSE. Hope this answer helps.
Step-by-step explanation:
Firstly, we have to find m∠J.
Since all the angles of a Δ equal 180°, angles J, L, and K should have a sum of 180°.
So,
m∠J + m∠L + m∠K = 180°
The diagram shows us that ∠L = 49° and ∠K = 90°, so we plug in those numbers in the equation.
m∠J + 49° + 90° = 180°
Then we simplify
m∠J + 139° = 180°
Subtract 139° to both sides
∠J = 41
Now the other angles.
Since ΔJKL ~ ΔRST, then ∠J ≅ ∠R, ∠K ≅ ∠S, and ∠L ≅ ∠T
Meaning, m∠J = m∠R, m∠K = m∠S, and m∠L = m∠T
Since we know m∠J = 41°, m∠K = 90°, and m∠L = 49° we could plug those in so...
41° = m∠R , 90° = m∠S , and 49° = m∠T
