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Tanya [424]
3 years ago
13

During a trip, a driver travelled a distance of 80km at an average speed of 60km/hr.He then changed his speed and travelled the

remaining 20km of his journey at 30km/hr. What was the drivers average speed for the entire journey?
Show all working!!​
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

50 km/hr

Step-by-step explanation:

D = RT

Time for first part of trip = 80/60 = 4/3 hr.

Time for second part of trip = 20/30 = 2/3 hr.

total time for entire trip = 4/3 + 2/3 = 6/3 = 2 hr.

Total distance = 100 km

Average rate of speed for entire trip = 100/2 = 50 km/hr

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For this case we have that by definition, the density is given by:

d = \frac {M} {V}

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According to the data of the statement we have:

d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g

So the volume is:

V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3

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3 years ago
Please help have only an hour please use picture
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Step-by-step explanation:

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Furniture store is having a sale where everything is 40% off.Write a function that represents the amount of discount d on an ite
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Answer:

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6 0
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Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:
tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

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Sort the dataset in ascending order

  • 79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

Q1 = \frac{N +1}{4}th

So, we have:

Q1 = \frac{13 +1}{4}th

Q1 = \frac{14}{4}th

Q1 = 3.5th

This is the average of the 3rd and the 4th element

Q1 = \frac{1}{2} \times (84 + 91)

Q1 = 87.5

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

Q3 =  3 \times \frac{N +1}{4}th

So, we have:

Q3 =  3 \times \frac{13 +1}{4}th

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This is the average of the 10th and the 11th element.

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<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

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Also, we have:

IQR(1.5) = 12 \times 1.5

IQR(1.5) = 18

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

Lower = Q_1 - IQR(1.5)

Lower = 87.5- 18

Lower = 69.5

Upper = Q_3 + IQR(1.5)

Upper = 99.5 + 18

Upper = 117.5

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0
2 years ago
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