All categories

2 years ago

Why don't we see other stars during day?

Physics

2 answers:

Jlenok [28]2 years ago

8 0

They aren’t visible because the sun is shining bright but at night it’s dark and they really pop

Monica [59]2 years ago

5 0

Answer:

Stars aren't visible during the sunlit hours of daytime because the light-scattering properties of our atmosphere spread sunlight across the sky. Seeing the dim light of a distant star in the blanket of photons from our Sun becomes as difficult as spotting a single snowflake in a blizzard.

Explanation:

You might be interested in

How are galaxies organized and distributed within the universe

den301095 [7]

The galaxies aren't distributed randomly throughout the universe but they are grouped in gravitationally bound clusters.

3 0

3 years ago

Read 2 more answers

In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6

Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

$\lambda = \dfrac{h}{mv}$

$1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}$

$v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}$

v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

$E = \dfrac{1}{2}mv^2$

$E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2$

E = 2.5 x 10⁻¹⁴ J

8 0

3 years ago

In calisthenics, the resistance is ultimately provided by __________. A. free weights B. springs and elastic bands C. gravity D.

tangare [24]

Answer:

I think the answer is b am sorry if it is wrong

Explanation:

5 0

2 years ago

Read 2 more answers

The mussels are not native to the lakes, and they have begun to kill native mussels by attaching to them and covering them up. T

Tanya [424]

The zebra mussels are an invasive species

4 0

3 years ago

Which statement is correct?

Sedbober [7]

Answer:

The answer is "Choice C ".

Explanation:

The relationship between the E and V can be defined as follows:

$\to E= -\Delta V$

Let,

$\to E= \frac{\delta V}{\delta x}$

When E=0

$\to \frac{\delta V}{\delta x}=0$

v is a constant value

Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.

7 0

2 years ago