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Novay_Z [31]
2 years ago
14

Why don't we see other stars during day?

Physics
2 answers:
Jlenok [28]2 years ago
8 0
They aren’t visible because the sun is shining bright but at night it’s dark and they really pop
Monica [59]2 years ago
5 0

Answer:

Stars aren't visible during the sunlit hours of daytime because the light-scattering properties of our atmosphere spread sunlight across the sky. Seeing the dim light of a distant star in the blanket of photons from our Sun becomes as difficult as spotting a single snowflake in a blizzard.

Explanation:

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Ride and average of 15mph for 30 miles, how long does it take?
dalvyx [7]

Answer:

2 hrs

Explanation:

time = distance ÷ speed

3 0
3 years ago
A force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s^2. If a force of 5 newtons is applied to a mass o
nignag [31]

For any force and any mass, the acceleration is always

(the strength of the force) divided by (the mass) .

If a force of 5 newtons is applied to a mass of 5 kg, the acceleration will be

(5 Newtons) / (5 kg) = <em>1 m/s²</em>

7 0
3 years ago
In the periodic table, the properties repeat in what direction?​
pogonyaev

Answer:

Left to right and top to bottom

Explanation:

On the periodic table, the properties repeat from left to right and from top to bottom.

Periodic properties have a pattern from the top to the bottom or down a group or family.

Also, across the period from left to right, they also show a repeating pattern.

  1. Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
  2. Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.
7 0
3 years ago
Is a dog chasing its tail acceleration
AfilCa [17]

Answer:

if he is chasing his tail faster with each circle, then that would be acceleration, If not then no

7 0
2 years ago
Read 2 more answers
We are going to make an imaginary engine using water. We are going to heat 100 grams of water to 120 C from its initial temperat
Svetach [21]

Answer:

The work done by this engine is 800 cal

Explanation:

Given:

100 g of water

120°C final temperature

22°C initial temperature

30°C is the temperature of condensed steam

Cw = specific heat of water = 1 cal/g °C

Cg = specific heat of steam = 0.48 cal/g °C

Lw = latent heat of vaporization = 540 cal/g

Question: How much work can be done using this engine, W = ?

First, you need to calculate the heat that it is necessary to change water to steam:

Q_{1} =m_{w} C_{w} (100-22)+m_{w}L_{w}+m_{w}C_{g}(120-100)

Here, mw is the mass of water

Q_{1} =(100*1*78)+(100*540)+(100*0.48*20)=62760cal

Now, you need to calculate the heat released by the steam:

Q_{2} =m_{w}C_{g}(120-100)+m_{w}L_{w}+m_{w}C_{w}(100-30)=(100*0.48*20)+(100*540)+(100*1*70)=61960cal

The work done by this engine is the difference between both heats:

W=Q_{1}-Q_{2}=62760-61960=800cal

8 0
3 years ago
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