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Lynna [10]
3 years ago
12

Helppppp!!!!!! inportant need help with b​

Physics
1 answer:
KengaRu [80]3 years ago
8 0
I believe the answer is either 1.6 or 9.8
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Give an example of a situation in which you would describe an
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a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien
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Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

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Using the definition of the centripetal force we have:

\Sigma F=ma_{c}=m\frac{v^{2}}{R}

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<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

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3 years ago
1. The gravitational force acting on a falling body and its weight is constant. But the law of universal gravitation tells us th
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It's not so much a "contradiction" as an approximation. Newton's law of gravitation is an inverse square law whose range is large. It keeps people on the ground, and it keeps satellites in orbit and that's some thousands of km. The force on someone on the ground - their weight - is probably a lot larger than the centripetal force keeping a satellite in orbit (though I've not actually done a calculation to totally verify this). The distance a falling body - a coin, say - travels is very small, and over such a small distance gravity is assumed/approximated to be constant.
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3 years ago
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