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3 years ago

Can someone help me with these physics questions?

Physics

1 answer:

wariber [46]3 years ago

6 0

hi! Glad to help =)

1. would be c

2 would be d

3 would be A

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The scientific method is

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A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

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3 years ago

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A 3.0N force to the right acts on a 0.5kg object at rest during a time interval of 4.0 seconds .What is the velocity of the obje

monitta

Answer:

24 m/s

Explanation:

Applying Newton's second law of motion,

F = ma................ Equation 1

Where F = force acting on the object, m = mass of the object a = acceleration of the object.

First we calculate for a.

make a the subject of the formula in equation 1 above

a = F/m............... Equation 2

Given: F = 3 N, m = 0.5 kg.

Substitute into equation 2

a = 3/0.5

a = 6 m/s²

Secondly we calculate the velocity by using,

v = u+at................... Equation 3

Where v = Final velocity of the object, u = initial velocity of the object, t = time interval

Given: u = 0 m/s (at rest), a = 6 m/s², t = 4 s

Substitute into equation 3

v = 0+6(4)

v = 24 m/s

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3 years ago

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A light-year is the distance that light travels in one year. The speed of light is 3.00 × 108 m/s. How many miles are there in o

Alinara [238K]

Answer:

(a) $5.88\times 10^{12}mi$

Explanation:

We have given speed of light $c=3\times 10^8m/sec$

Given time = 1 year =365 days

We know that in 1 minute = 60 sec

1 hour = 60×60 = 3600 sec

In one day = 24 hour = 24×60×60=86400 sec

So in 365 days = 365×86400 $=3.1536\times 10^7sec$

We know that distance = speed ×time $=3.1536\times 10^7\times 3\times 10^8=9.46\times 10^{15}m$

We have given that 1 mi = 1609 m

So $9.46\times 10^{15}m=\frac{9.46\times 10^{15}}{1609}=5.88\times 10^{12}mi$ So option (a) is correct

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3 years ago

A mass m = 75 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 19.2 m and finally

dalvyx [7]

Answer:

The velocity is 19.39 m/s

Solution:

As per the question:

Mass, m = 75 kg

Radius, R = 19.2 m

Now,

When the mass is at the top position in the loop, then the necessary centrifugal force is to keep the mass on the path is provided by the gravitational force acting downwards.

$F_{C} = F_{G}$

$\frac{mv^{2}}{R} = mg$

where

v = velocity

g = acceleration due to gravity

$v = \sqrt{2gR} = \sqrt{2\times 9.8\times 19.2} = 19.39\ m/s$

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3 years ago

A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?

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The frequency doesn't change. If the wavespeed increases, then the wavelength must also increase ... It's just the distance the wave travels during each complete wiggle.

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