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damaskus [11]
2 years ago
5

Two spheres carry a charge of 1x10^-7 C. Their centers are separated by 0.7m. Calculate the magnitude of the force between the t

wo charged objects.
Write your answer in scientific notation using one significant figure

PLEASE HELP ME
Physics
1 answer:
Drupady [299]2 years ago
8 0

We have that the  force between  the two charged objects is mathematically given as

F=2.349N

<h3>Magnitude of the force between  two charged objects.</h3>

Question Parameters:

Two spheres carry a charge of 1x10^-7 C.

Their centers are <u>separated</u> by 0.7m.

Generally the equation for the Force  is mathematically given as

F=\frac{q1q2}{4*\pi e*r}

Therefore

F=\frac{(1e-7)^2}{9e9*0.7}

F=2.349N

For more information on Force visit

brainly.com/question/26115859

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Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

r=\dfrac{\mu_oNI}{2\pi B}  

r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}  

r = 0.00523 m

or

r=5.23\times 10^{-3}\ m

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

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I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app
Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

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2 years ago
If a man weight 155 lb on earth, specify
Natali [406]
For the answer to the question above, on Earth, a one-pound object has a mass of about 0.453592 kilograms. 

<span>Therefore the man's mass is 155 * 0.453592 = 70.30676 kilograms. </span>

<span>The part about the Moon's gravity is irrelevant. While the weight of a person or object would be different on the Moon, the mass would be the same.</span>
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If you put two identical cars on opposite sides of a large magnet, what happens
FrozenT [24]

Answer:

Depends on what pole it is.

Explanation:

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If a marble is released from a height of 10 meters how long would it take to hit the ground?
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<span>t^2 ~ 2.04 </span>

<span>t ~ 1.43 seconds</span>
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