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Alexxx [7]
2 years ago
11

What is the x-intercept of the equation 4x - 5y = - 20

Mathematics
1 answer:
allsm [11]2 years ago
6 0

Answer:

x=-5

Step-by-step explanation:

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Jason needs to find the volume of the sphere shown below. Which formula should be used ?
Fiesta28 [93]

Answer:

dont see sphere

Step-by-step explanation:

3 0
2 years ago
The two lines y= 6x+15 and y= mx+4 intersect at x= -2. What is the y-coordinate of their intersection point
taurus [48]

Answer:

The y-coordinate of their intersection point is 3

That is y=3

Step-by-step explanation:

Given two lines are y=6x+15 and y=mx+4

Given that the two lines intersect at x=-2

To find the y coordinate of their intersection point :

Equating the two lines

6x+15=mx+4

6x+15-mx-4=0

6x-mx+11=0

(6-m)x+11=0

At x=-2  (6-m)x+11=0

(6-m)(-2)+11=0

(6-m)(-2)=-11

6-m=\frac{11}{2}

-m=\frac{11}{2}-6

-m=\frac{11-12}{2}

-m=\frac{-1}{2}

m=\frac{1}{2}

Substitute the value m=\frac{1}{2} in y=mx+4 we get

y=\frac{1}{2}x+4

At x=-2 y=\frac{1}{2}(-2)+4

=-1+4

=3

Therefore y=3

Therefore the y-coordinate of their intersection point is 3

7 0
3 years ago
The area of the rectangle is 24 inches. How much longer is its length than its width?
antiseptic1488 [7]
I Belive That There Can't Be 3 Numbers In A Rectangle Because At The Top You Get 24 And 6 And I Think It Is BxH One Half Times Base Times Height So 2xBxH . 
8 0
3 years ago
Please answer this question now
larisa [96]

Answer:

1471.15

Step-by-step explanation:

4 0
3 years ago
Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

7 0
3 years ago
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