Answer:
or
Step-by-step explanation:
<u>Step 1: Cross Multiply</u>
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<u>Step 2: Divide both sides by 2.35</u>
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or
Answer: or
PLZZZ HURRY!!!!!
2 answers:
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<u>Given</u>:
The sum of 5 consecutive integers is 110.
Let the sequence be x, x + 1, x + 2, x + 3, x + 4
We need to determine the fourth number in the sequence.
<u>Value of x:</u>
Since, the sum of 5 consecutive integers is 110.
Thus, we have;
Adding the like terms, we have;
Thus, the value of x is 20.
<u>Fourth term:</u>
The fourth term of the sequence is x + 3
Substituting x = 20 in the term, we get;
Fourth term = 20 + 3 = 23
Thus, the fourth term of the sequence is 23.
Answer: x^2+^3.x^3x+4 (x2-x-6)-(x^2-x-6) (y^2-2y-8)+(y^2+y-12)
Step-by-step explanation:
