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Delvig [45]
3 years ago
8

A circle has a diameter of 32in. Find the circumference of the circle to the nearest tenth.

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
Radius is 16in
Circumference is 2xpiXradius
So 100.5 inch
You might be interested in
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
Solve <br> (3x) 9 = (4x) 5
Leto [7]

Answer:

4 = 1x

Step-by-step explanation:

(3x)9 = (4x)5

9 = (1x) 5

4 = 1x

6 0
3 years ago
This question has been deleted
Serhud [2]
What is the question
7 0
3 years ago
It took Everly 55 minutes to run a 10-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu
slega [8]
\bf \cfrac{10km}{55mins}\cdot \cfrac{0.621miles}{1km}\implies \cfrac{62.1miles}{55mins}\approx 1.12909909\approx \boxed{1.13\frac{miles}{mins}}
5 0
3 years ago
I don’t know how to do these problems so please help me.
Olin [163]

Answer:

36s^3

Step-by-step explanation:

3 0
3 years ago
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