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Lelu [443]
3 years ago
8

Pleasee answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer:3.6

Step-by-step explanation:

Elodia [21]3 years ago
3 0

Answer:

3.6

Step-by-step explanation:

Distance = √(x2 - x1)² + (y2 - y1)²

√(5 - 3)² + (-2 - 1)²

√13 = 3.605

<em>good luck, i hope this helps :)</em>

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The ratio of girls to boys in the grade is 9 to 10. If there are 225 girls, how many boys are there?
MArishka [77]

Answer:

250 boys

Step-by-step explanation:

We know that the ratio is 9:10 from girls to boys

Take 225 and divide it by 9

225 ÷ 9 = 25

So we know that 25 is a factor of 225

We can the number of boys and multiply it by 25 to get 250

If we put it in the ratio form:

225:250 = 9/10

Check work:

25 x 9 = 225

25 x 10 = 250

5 0
4 years ago
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25+ POINTS WILL MARK BRAINLIEST
Katen [24]

Answer:

Point A = (-6,0)

Point B = (0,4)

7 0
3 years ago
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HELP ME<br> 5x - 4 = 5x +7
pav-90 [236]

Answer:

x = 11

Step-by-step explanation:

First, you have to add four to both sides to get

5x = 5x + 11

Now, you have to subtract 5x on both sides to get

x = 11

:) Good luck!

8 0
3 years ago
Read 2 more answers
A number to the 10th power divided by the same number to the 7th power equals 216
VashaNatasha [74]

Answer: 5

Step-by-step explanation: Let x = the number

x^10 ÷ x^7 = 125

x^3 = 125

x = 5

6 0
3 years ago
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What is the area of the trapezoid shown? trapezoid A = ______ units²?
notka56 [123]

Answer:

74.1 units²

Step-by-step explanation:

Area of the trapezoid shown = ½×(AD + BC)×BE

Use distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to find AD, BC, and BE.

✍️Distance between A(-9, 4) and D(9, 1):

AD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(9 -(-9))^2 + (1 - 4)^2}

= \sqrt{(18)^2 + (-3)^2}

= \sqrt{(324 + 9} = \sqrt{333}

AD = 18.2 units (nearest tenth)

✍️Distance between B(-4, -3) and C(2, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2 -(-4))^2 + (-4 -(-3))^2}

= \sqrt{(6)^2 + (-1)^2}

= \sqrt{(36 + 1} = \sqrt{37}

BC = 6.1 units (nearest tenth)

✍️Distance between B(-4, -3) and E(-3, 3):

BE = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-3 -(-4))^2 + (3 -(-3))^2}

= \sqrt{(1)^2 + (6)^2}

= \sqrt{(1 + 36} = \sqrt{37}

BE = 6.1 units (nearest tenth)

✔️Area of the trapezoid:

Area = ½×(AD + BC)×BE

Plug in the values into the formula

Area = ½×(18.2 + 6.1)×6.1

Area = ½×(24.3)×6.1

Area = 74.115 ≈ 74.1 units² (nearest tenth)

5 0
3 years ago
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