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Snowcat [4.5K]
2 years ago
11

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! WILL NAME BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Fudgin [204]2 years ago
8 0
55% is the correct answer
faltersainse [42]2 years ago
5 0

Hope this helps

Answer :

Percentage increase = (279 - 180)/180 x 100% = 55%

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Sebastián está haciendo un curso de patinaje. El primer día recorrió una distancia de
jeyben [28]
Sorry but I don’t understand your language.
8 0
3 years ago
Ill mark brainliest I just don't understand
Misha Larkins [42]

Answer:

a triangle always equals 180 degrees so

63+ 2x+8 + x+7 =180

solve for x

and then plug it back into original equation

let me know if this makes sense

glad to help you more if needed

Step-by-step explanation:

3 0
3 years ago
Which best defines the relashionship between speed and velocity 1.speed is velocity with displacement 2.velocity is speed with d
katrin [286]

Answer:

  3.  Speed is based on a specific direction

Step-by-step explanation:

Generally, speed is a scalar quantity equal to the magnitude of velocity. Velocity is a vector quantity that is speed together with a specific direction.

The answer choice that seems most in agreement with this description seems to be ...

  3. Speed is based on a specific direction

3 0
3 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
Pls fastttttttttttttttt​
Lera25 [3.4K]

a= -1, b= 2 & c= -3

abc= -1 x 2 x -3

= 6

6 0
2 years ago
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