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const2013 [10]
2 years ago
8

M= i + r ; solve for r

Mathematics
1 answer:
Alex777 [14]2 years ago
7 0

Answer:

m - i = r

Step-by-step explanation:

In this question, you are solving for "r".

Solve:

M= i + r

We have to get "r" by itself, so subtract "i" from both sides.

m - i = r

Since we found what "r" is, we can't solve any further.

m - i = r would be your answer.

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Suppose that a is a one-dimensional array of ints with a length of at least 2. Which of the following code fragments successfull
elixir [45]

Answer:

E)II and III only

Step-by-step explanation:

This can be seen with examples. Say a[0]=1 and and a[1]=2.

for I , the first line of code would be:

a[0]=a[1];

thus, we would get a new value for a[0]=2.

The second line of code

a[1]=a[0]; uses the new value of a[0], so we would get a[1]=2.

The end result is a[0]=2, and a[1]=2 which doesn't exchange the values of the first two elements.

For II the first line of code

int t= a[0]; saves the original value of a[0] to t, so we get t=1.

the second line of code

a[0]=a[1]; changes the value of a[0]  to that of a[1]. Thus, in our example a[0]=2.

the final line

a[1]=t; changes the value of a[1] to the original value of a[0], giving us a[1]=1 and a[0]=2, what we were looking for.

For III

the first line of code

a[0]=a[0]-a[1];

gives us

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the secon line

a[1]=a[1]+a[0];

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the last line

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a[0]=1-(1-2)=1-1+2=2

which exchanges the values needed.

So we can see that only II and III do what we require, giving us E as the answer.

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Step-by-step explanation:

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