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3 years ago

If you apply for a job with Globo Corp, there is a 75% chance that you will get an interview.

Mathematics

1 answer:

aivan3 [116]3 years ago

6 0

Answer:

The probability that you will get the job If you apply for a job with Globo Corp=0.36

Step-by-step explanation:

We are given that

If you apply for a job with Globo Corp, then the probability of getting interview P(A)=75%=0.75

If you get an interview, then the probability of getting job=P(B)=48%=0.48

We have to find the probability that you will get the job If you apply for a job with Globo Corp.

If you apply for a job with Globo Corp, the probability of getting job= $P(A)\times P(B)$

If you apply for a job with Globo Corp, the probability of getting job= $0.75\times 0.48$

If you apply for a job with Globo Corp, the probability of getting job=0.36

Hence, the probability that you will get the job If you apply for a job with Globo Corp=0.36

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Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

$38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\$ $54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79$

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = $\frac{55+59}{2} = \frac{114}{2}=57$

In point b:

First-quarter $Q_1 = \frac{1}{4} \text{number of 8th call}$

$=\frac{1}{4} \times 30 th \\\\= 7.5 th$

The first quarterlies are $7.5th \ \ that \ is = (7+0.5)th\ \ term$

therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

$=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times 30 th \\\\=22.5 \ th = (22+0.5)th \ \ term$

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

$= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5$

In point c:

First decile $D_1 = \frac{1}{18} \text{number of 8th call}$

$= \frac{1}{10} \times 30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times 8\ th\ call\\\\=\frac{9}{10} \times 30 th \\\\=27th \ \ term\\\\\to D9 = 67$