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Flura [38]
3 years ago
13

What is the slope of the line that contains the points (13,-2) and (3.-2)

Mathematics
1 answer:
Allushta [10]2 years ago
8 0

Points are

  • (13,-2)
  • (3,-2)

\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}

\\ \sf\longmapsto m=\dfrac{3-13}{-2+2}

\\ \sf\longmapsto m=\dfrac{-10}{0}

\\ \sf\longmapsto m=0

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Flura [38]

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Answer: C (0,2)

Step-by-step explanation: Y intercept is when the x value is equal to 0. Find the value in the table where the x value is 0 and then look at the h(x) value or the y value to find the answer. In this case the point where x=0 h(x) = 2.

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ahrayia [7]

Answer:

Claim 2

Step-by-step explanation:

The Inscribed Angle Theorem* tells you ...

... ∠RPQ = 1/2·∠ROQ

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... 2·∠RPQ = ∠ROQ

The symmetric property of equality says you can rearrange this to ...

... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ

_____

* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.

You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.

4 0
3 years ago
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