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Flura [38]
3 years ago
13

What is the slope of the line that contains the points (13,-2) and (3.-2)

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Points are

  • (13,-2)
  • (3,-2)

\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}

\\ \sf\longmapsto m=\dfrac{3-13}{-2+2}

\\ \sf\longmapsto m=\dfrac{-10}{0}

\\ \sf\longmapsto m=0

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(AP Calc) the graph of the function f shown above has three line segments....
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3 years ago
HIGH POINTS AND BRAINLY !!!<br>PLEASE<br>PLEASE HELP <br><br>Horrible at math <br><br>Paper attached
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Answer:

I have to go so I am not able to write all the answers but you can use the explanation. I tried my best. I hope this helps. Please mark me brainly!

Step-by-step explanation:

To write a perpendicular equation to this one, first, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. I hope this helps. Please mark me brainly!

8 0
3 years ago
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Step-by-step explanation:

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Hope it will help you

3 0
3 years ago
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