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katen-ka-za [31]
3 years ago
12

Mrs. Smedema likes cookies. Each student in her 8th grade math class presented her with a cookie. One-third of the students each

gave her an oatmeal cookie, one-sixth of the students each gave her a cinnamon cookie, one-fourth of the students each gave her a chocolate chip cookie, and the remaining 9 students each gave her a peanut butter cookie. How many students are in Mrs Smedema’s 8th grade math class?
Mathematics
1 answer:
raketka [301]3 years ago
6 0

Late answer, but whatever.

Answer:

36. There are 36 students in the class.

Step-by-step explanation:

4/12 oatmeal

2/12 cinnamon

3/12 chocolate

9 peanut

The fractions added together = 9/12

This means the 9 students = 3/12 of the class

3 x 4 = 12

9 x 4 = 36

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Jennifer buys a block of clay for an art project. The block is shaped like a cube with edge lengths of 12 inches.
Gnoma [55]

Answer:

Volume of block Jennifer bought:

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Volume of sphere Jennifer wanted to make:

V = (4/3) x pi x radius^3 = (4/3) x pi x (4/2)^3 = 33.5 (in3)

a, The number of spheres she can make:

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3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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svetoff [14.1K]
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This is the answer you are looking for. I hope this helps :)
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