C, anything linear equations only have one variable
Answer:
c
Step-by-step explanation:
yeah tha answer is c I can't explain it rn but for now put c
Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer: x = 15
Answers:
- first box = 1
- second box = 1
- third box = 3
- fourth box = 3
Refer to the graph below.
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Explanation:
If f(x) is an even function, then f(-x) = f(x) for all x in the domain.
What this means is that we have symmetry about the y axis. We can reflect that given curve over the y axis to generate the missing left side.
The graph shows that (1,1) is on the orange curve. It reflects over to (-1,1). This means 1 goes in the first box.
Use the rule
to apply a y axis reflection. We simply just change the sign of the x coordinate from positive to negative, while keeping the y coordinate the same.
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We can also see that (3,1) is also on the orange curve. It reflects over to (-3, 1) using that rule mentioned earlier.
1 goes in the second box
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The graph your teacher gave you shows that if we plugged in x = 5, then we get y = 3. In other words, the point (5,3) is on the orange graph.
It reflects over to (-5, 3) to show that x = -5 leads to the output y = 3
3 goes in the third box
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Lastly, the point (6,3) reflects to (-6,3) when reflecting over the y axis.
3 goes in the fourth box.
See the graph below.
Answer:
k = -2
Step-by-step explanation:
Divide 22 by -11 as well as -11k by -11
(You have to divide both sides by the number that k is to find your answer)
22 divided by -11 = -2
-11k divided by -11 = k
meaning you would get the answer of k = -2