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lapo4ka [179]
3 years ago
10

Anais bought 2 1/2 yards of ribbon. She had 1 foot 6 inches of ribbon left after trimming some curtains. How many inches of ribb

on did Anais use to trim the curtains?
Mathematics
2 answers:
vlada-n [284]3 years ago
6 0
2 1/2 yards = 7.5 ft
1 foot and 6 inches = 1.5 ft
7.5-1.5 = 6
6 ft = 72 inches
Anais used 72 inches of ribbon.
svetoff [14.1K]3 years ago
6 0
1.5 yards = 54 inches
1ft 6 inches  = 18 inches

54 inches + 18 inches = 72 inches

The answer is anais used 72 inches of ribbon.
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Divide and find quotient<br>(a⁴-b⁴) ÷ (a+b)<br>(step by step explanation)​
lakkis [162]

Answer:

Step-by-step explanation:

(a⁴-b⁴)/(a-b)

using..(a+b²)=(a+b)(a-b)

=(a²+b²)(a²-b²)/(a-b)

=(a²+b²)(a+b)(a-b)/(a-b)

=(a²+b²)(a+b)

6 0
1 year ago
An electric bulb is sold in a box measuring 5 cm by 4 cm by 4 cm. If the shopkeeper receives them in a carton measuring 50 cm by
katen-ka-za [31]

Answer:

250

Step-by-step explanation:

Bulb box and carton both are of cuboidal shape.

<u>For bulb </u><u>box</u><u> </u><u>the </u><u>d</u><u>imensions</u><u> </u><u>are:</u>

  • l = 5 cm, w = 4 cm, h = 4 cm

  • V_{Bulb\: box} =lwh

  • \implies V_{Bulb\: box} =5(4)(4)

  • \implies V_{Bulb\: box} =80\: cm^3

<u>For </u><u>Carton </u><u>the dimensions are</u><u>:</u>

  • l = 50 cm, w = 20 cm, h = 20 cm

  • V_{Carton} =lwh

  • \implies V_{Carton} =50(20)(20)

  • \implies V_{Bulb\: box} =20,000\: cm^3

To find the number of bulbs packed in the carton, divide the V_{Carton} by V_{Bulb\: box}

  • Number \:of \:bulbs =\frac{V_{Carton}}{V_{Bulb\: box}}

  • \implies Number \:of \:bulbs =\frac{20,000}{80}

  • \implies Number \:of \:bulbs = 250

So, 250 bulbs will be packed in one carton.

3 0
2 years ago
Please help me fast, best answer will get brainliest.​
Ipatiy [6.2K]

Answer:

Answer is below

Step-by-step explanation:

The outliers are 20 and 78 because they are not close to the other numbers. They have a great difference between them and the other numbers.

3 0
3 years ago
Simplify:<br>3×5-1-(2² +6÷2)​
ivanzaharov [21]

Answer:

7

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The LCM of two numbers is 48. The number one in the ratio 2:3. Then Sum of the numbers is:
Oksi-84 [34.3K]

Answer:

40

Step-by-step explanation:

Let the numbers be 2x and 3x

Then their L.C.M. = 6x

BUT also their LCM=48

6x=48

x=48/6

x=8

So,

First number=2x=2x8=16

Second number=3x=3x8=24

The numbers are 16 and 24.

Hence required sum =(16+24)=40

So none of the options are correct

6 0
2 years ago
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