If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
The question is, "how many ways ...".
There are as many ways to solve a math problem as you can think of. (Some are shorter or easier than others.)
Essentially, an infinite number.
Answer: 125 yards?
Step-by-step explanation:
I think this is the answer
Answer:
3x-5
Step-by-step explanation:
(6x+5)-(3x+10) = 6x+5-3x-10
= 3x-5
