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2 years ago

Write a polynomial function of least degree with rational coefficients so that P(x)0 has the given roots. x=-5, x=10

Mathematics

1 answer:

Maru [420]2 years ago

8 0

Answer:

P(x) = x² - 15x + 50

Step-by-step explanation:

We write the polynomial function P(x), given that P(x) = 0 has the given roots, x = 5 and x = 10.

Since x = 5 and x = 10 are the roots of P(x) = 0, it follows that (x - 5) and (x - 10) are factors of P(x) = 0. So, P(x) = (x -5)(x - 10) = 0

Expanding the brackets, we have

x² - 10x - 5x + 50 = 0

Simplifying, we have

x² - 15x + 50 = 0 = P(x)

Thus,

P(x) = x² - 15x + 50

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Hi there!

Let's solve this problem step by step!
$f(x) = \frac{1}{8} (8 {}^{x})$

To find f(3) we must substitute x = 3 into the formula.
$f(3) = \frac{1}{8} (8 {}^{3} )$

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
$f(3) = \frac{1}{8} \times 512$

And finally multiply.
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Hence, the answer is D. 64.
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Write a polynomial function of least degree with rational coefficients so that ​P(x)0 has the given roots. x=-5, x=10

Write a polynomial function of least degree with rational coefficients so that P(x)0 has the given roots. x=-5, x=10