From my work I believe it should be the third one.
Answer:
137/(36π) ft/s
Step-by-step explanation:
The rate of change of volume will be the product of the rate of change of radius and the area of the sphere. The area of the sphere is ...
A = 4πr² = 4π(6 ft)² = 144π ft²
Then the relationship above is ...
dV/dt = A·dr/dt
548 ft³/s = (144π ft²)·dr/dt
dr/dt = (548 ft³/s)/(144π ft²) = 137/(36π) ft/s ≈ 1.2113 ft/s
Answer:
8.2
Step-by-step explanation:
If each student in the group collected 15 shells, we know that there are 123 students on the field trip, so we can take 123 and divide it by 15 to get 8.2 or 41/5.
<h2>Given :-</h2>
In □PQRS side PQ∥ side RS. If m∠P = 108degree
and m∠R = 53degree
<h2>To Find :-</h2>
m∠Q and m∠S.
<h2>Solution :-</h2>
According to angle sum property
P∠Q=180−∠P
∠Q=180−108
For angle S
∠S=180−∠R
∠S=180−53
Answer:
34
Step-by-step explanation:
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