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andreev551 [17]
3 years ago
8

Solve the problem.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0
Answer is the B Sure let’s gooo
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A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
What acronym is used for sine , cosine and tangent
sergejj [24]

Answer:

SOHCAHTOA.

Step-by-step explanation:

acronym is an abbreviation formed from the initial letters of other words and pronounced as a word

The acronym for sin cosine and tangent is

SOHCAHTOA

Sine =Opposite over Hypotenuse

Cosine= Adjacent over Hypotenuse

Tangent= Opposite over Adjacent

8 0
3 years ago
-3x^2+6x+1=4 find the discriminant of each quadratic equation then state the number and type solutions
ipn [44]

Answer:

S={( 1 )}

Step-by-step explanation:

-3x²+6x+1=4

-3x²+6x+1-4=0

-3x²+6x-3=0

∆=b²-4.a.c

∆=(6)²-4.(-3).(-3)

∆=36-36

∆=0

x'=x"=-b/2a=-(+6)/2.(-3)=-6/-6=1

3 0
3 years ago
Read 2 more answers
Math Help! <br>Answer questions with work
taurus [48]
The answer is 14 because you just have to pick a number to work with so it is 14.
6 0
3 years ago
Please help me with this
creativ13 [48]

Answer:

Step-by-step explanation:

(-3,-2)

7 0
3 years ago
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