Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
-61 degrees F
Step-by-step explanation:
1) C. <u>19.4
</u>1/3(3)^3 + 5.2(2)
1/3(27) + 10.4
9 + 10.4
= 19.4
2) C. <u>6
</u>9 - (1/2)^4 * 48
9 - 0.0625 * 48
9 - 3
= 6
3) A. <u>2 times y divided by 7</u>
4) C. <u>5p - 4</u>
5) C. <u>Step 2; 4(2) + 4(4x)
</u>Hope this helps!<u>
</u>
Answer:
starts wuth 46, and sells half, so she has 23. then when she buys 17 more she then has 40.
if you are asked to show work its 46/2=23, then 23+17=40!
