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ddd [48]
2 years ago
9

THIS IS PART B So plz right answer

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
6 0

Answer:

that is confusing

Step-by-step explanation:

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For what values of x and y must the figure have in order to be a parallelogram
erma4kov [3.2K]

<u>Given</u>:

Given that the parallelogram with the lengths 5x, 3x + 1, 2y - 5 and y.

We need to determine the values of x and y.

<u>Values of x and y:</u>

We know the property that the opposite sides of a parallelogram are congruent.

Thus, we have;

5x=2y-5 ------- (1)

3x+1=y  ------- (2)

The value of x and y can be determined using the substitution method.

Substituting equation (2) in equation (1), we have;

5x=2(3x+1)-5

5x=6x+2-5

5x=6x-3

-x=-3

  x=3

Thus, the value of x is 3.

Substituting x = 3 in equation (2), we have;

3(3)+1=y

    9+1=y

         10=y

Thus, the value of y is 10.

5 0
3 years ago
Explain solving systems of equations using substition?
Nitella [24]

when solving a system of equations the difference between that and elimination is the when you're using the Elimination u have to first multiply the numbers but when substituting it's different unlike the Elimination this is all ik and can u mark me brainliest?

8 0
3 years ago
A 90% confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a
Stella [2.4K]

Answer:

b) We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $139,048 to $154,144.

Step-by-step explanation:

Confidence interval:

Confidence level of x%

We build from a sample.

Between a and b.

Intepretation: We are x% sure that the population mean is between a and b.

In this question:

90%

45 CEO's

Between ($139,048, $154,144).

So

We are 90% sure that the mean salary of all CEO's falls within this interval.

The correct answer is:

b) We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $139,048 to $154,144.

4 0
3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
3 years ago
Can someone answer this
Romashka [77]

Answer:

the answer is d  

Step-by-step explanation:

3 0
3 years ago
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