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MA_775_DIABLO [31]
3 years ago
15

A farm lets you pick 3 pints of raspberries for $12.00. Use any strategy you want to answer the questions below. 1. What is the

cost per pint? 2. How many pints do you get per dollar? 3. At this rate, how many pints can you afford for $20.00? 4. At this rate, how much will 8 pints of raspberries cost?
Mathematics
1 answer:
Stels [109]3 years ago
3 0

Answer:

$4 per pint

1/4 pint per dollar

5 pints for $20

$32 for 8 pints

Step-by-step explanation:

12.00/3 = 4

$4 per pint

1/4 = 1/4

1/4 pint per $1

$20 / $4 = 5 pints

$4 * 8 = $32

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I would like to create a rectangular orchid garden that abuts my house so that the house itself forms the northern boundary. The
son4ous [18]

Answer:

x  =  15 ft

y  =  15 ft

A(max)  =  225 ft²

Step-by-step explanation:

Let call  "x "  and  " y "  sides of the rectangle x (side paralll to the northern  boundary, then:

A(r)  = x*y        and      4*x  +  2*2*y  =  120   or    4*x  + 4*y  = 120

4*x  +  4*y  = 120    ⇒  x  +  y  = 30    ⇒   y  =  30 - x

Area of the garden as a function of x is:

A(x)  =  x* ( 30 - x )    ⇒  A(x)  =  30*x  - x²

Taking derivatives on both sides of the equation

A´(x)  = 30  - 2*x

A´(x)  = 0   ⇒    30  - 2*x =  0

2*x  =  30

x = 30/2

x = 15 ft

And  y =  ( 30 - x )

y  =  15 ft

A(max)  =  15*15

A(max)  = 225 ft²

8 0
3 years ago
Number 1d please help me analytical geometry
lesantik [10]
For a) is just the distance formula

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
%  (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}
-----------------------------------------------------------------------------------------
for b)  is also the distance formula, just different coordinates and distance

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
%  (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}
--------------------------------------------------------------------------
for c)  well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}

now.. whatever that is, is  = BC, so  the distance for BC is

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
%  (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d)   we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
%  (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\


\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"


7 0
3 years ago
Use the picture to figure out the combination.
dimulka [17.4K]
I think it’s 4952 but i’m not sure
3 0
2 years ago
What is 4/20 as a percent? And how do I find it?
Reika [66]
Well u know 4/20 equals 0.2 as a decimal but as a percentage it is 20% so 4/20 as a percentage is 20%
4 0
2 years ago
What is 2+2 and what is your favorite song?<br>​
melomori [17]

Answer:

2+2=4 and my fave song is blood in the water

Step-by-step explanation:

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3 0
3 years ago
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