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3 years ago

Choose the equation of the line that is parallel to the y-axis.

Mathematics

2 answers:

kodGreya [7K]3 years ago

4 0

Answer:

x=-2

Step-by-step explanation:

If x always = -2, it is a straight vertical line which means it is parallel to the y axis

kobusy [5.1K]3 years ago

3 0

It's x=-2 because anything just on the x axis without a y is vertical which is parallel to the y axis

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The graph of a linear function is shown on the grid. (-3,3.6) (5,2) What is the rate of change of y with respect to x for this f

lilavasa [31]

Answer:

rate of change = -0.32

Step-by-step explanation:

Rate of change = slope,m

$m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{3.6 - 2}{ - 3 - 2} \\ m = \frac{1.6}{ - 5} \\ m = \frac{ - 0.32}{1}$

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alexandr402 [8]

1. One way to approach this is to convert the magnitude and direction of each force to rectangular coordinates.

... first force = 90(cos(30°), sin(30°)) = (77.94, 45.00)

... second force = 50(cos(160°), sin(160°)) = (-46.98, 17.10)

Then their sum is

... resultant force = first force + second force = (30.96, 62.10)

The magnitude is found using the Pythagorean theorem:

... resultant magnitude = √(30.96^2 + 62.10^2)

... ... = √(958.52+3856.41) = √4814.93

... ... = 69.39

The resultant direction can be found using the definition of the tangent function.

... tan(α) = 62.10/30.96 = 2.01

... α = arctan(2.01) = 63.55°

The (magnitude, direction) of the resultant force are (69.39, 63.55°).

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(Note that rounding introduced an error of 0.05° in the direction.)

2. Using DeMoivre's theorem, the magnitude of the 4th root is the 4th root of the magnitude, and the angle of the 4th root is 1/4 of the angle (and its aliases).

... fourth root = 256^(1/4)∠((240°+k*360°)/4) = 4∠(60°+k*90°) . . . . k=0, 1, 2, 3

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Pls help. I don't understand.

Nana76 [90]

Answer:

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Step-by-step explanation:

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Does the system of equations have no solution, one solution, or an infinite number of solutions? −5x+y=−1−5x+y=10

kherson [118]

Answer:

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Step-by-step explanation:

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

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3 years ago