So let's make p = dominant allele and q = recessive allele
p+q = 1, and (p+q)^2 = 1^2 thus
p^2 + 2pq + q^2 = 1, where p^2 = homozygous dominant, 2pq = heterozygous, and q^2 = homozygous recessive
So if p = .84, then q = 1-.84 = .16
a) recessive phenotype = q^2 = (.16)^2 = .0256
= 2.6%
b) dominant allele = p = .84 = 84%
c) heterozygous genotype = 2pq = 2(.84)(.16)
= .269 = 26.9%
Answer:
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