Question

Write the balanced equation for the reaction that occurs when aluminum bromide is mixed with potassium sulfate forming potassium bromide and aluminum sulfate

Answer 1

Answer:

  2AlBr₃  +  3K₂SO₄ →   6KBr  +  Al₂(SO₄)₃

Explanation:

Given species;

  Reactants

    Aluminum bromide  = AlBr₃

    Potassium sulfate = K₂SO₄

Products

    Potassium bromide  = KBr

    Aluminum sulfate = Al₂(SO₄)₃

 So, the reaction equation is given as:

          AlBr₃  +  K₂SO₄ →   KBr  + Al₂(SO₄)₃

To balance this chemical equation, let us an algebraic approach;

        aAlBr₃  +  bK₂SO₄ →   cKBr  +  dAl₂(SO₄)₃

Conserving Al;

        a  = 2d

   Conserving Br;

        3a  = c

   Conserving K;

       2b  = c

     Conserving S;

       b  = 3d

     Conserving O;

      4b  = 12d

    if a  = 1;

        c = 3

       b = $\frac{3}{2}$

        d  = $\frac{1}{2}$  

 Now, multiply through by 2;

  a  = 2, b  = 3, c = 6 and d = 1

      2AlBr₃  +  3K₂SO₄ →   6KBr  +  Al₂(SO₄)₃