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myrzilka [38]
3 years ago
9

A sample of a substance has a volume of 60.5ml and a density of 1.20g/ml what is density of magneis

Chemistry
1 answer:
erica [24]3 years ago
8 0

Answer:

m = 72.6 grams

Explanation:

Given that,

The density of the substance uis 1.2 g/mL

Volume, V = 60.5 mL

We need to find the mass of the substance. Density is equal to mass divided by its volume. So, it can be given by :

d=\dfrac{m}{V}\\\\m=d\times V\\\\m=1.2\ g/mL\times 60.5\ mL\\\\m=72.6\ g

So, the mass of the substance is 72.6 grams.

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Can anyone help with 5 through 8? Please :(
Aleksandr [31]

Answer:

The answer to your question is below

Explanation:

5)        Fe₂O₃(s)   +  3H₂O   ⇒    2Fe(OH)₃ (ac)        Synthesis reaction

6)        2C₄H₁₀(g)  + 13O₂(g)  ⇒   8CO₂ (g)  +  10H₂O   Combustion reaction

7)         2NO₂ (g)  ⇒   2O₂ (g)  +  N₂ (g)                     Decomposition reaction

8)         H₃P (g) +  2O₂ (g)  ⇒    PO (g)  +   3H₂O  Single replacement reaction

4 0
3 years ago
3. Calculate the volume, in mL, of 100.0 g of alcohol, if the density is 0.79 g/mL.
Naya [18.7K]

Answer:

The answer is

<h2>126.58 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

<h3>volume =  \frac{mass}{density}</h3>

From the question

mass of alcohol = 100 g

density = 0.79 g/mL

The volume is

volume =  \frac{100}{0.79}  \\  = 126.58227848...

We have the final answer as

<h3>126.58 mL</h3>

Hope this helps you

4 0
3 years ago
Could someone please care to explain what the answer is
polet [3.4K]

Calculate the percentage composition of Ca(MnO4)2.

<u>Firstly, we see how many atoms are there for each element in the formula</u>.

Ca= 1 atom

Mn= 2 atoms

O= 8 atoms

<u>Next, we are going to consult our periodic table for the atomic mass of each element.</u>

Ca= 40

Mn= 55

O= 16

Then, we have to find the molar mass for the compound..

Here is the formula for calculating molar mass of an element:

Molar Mass= ( no. of atoms of the element × atomic mass of the element)

Now, we have to calculate the atomic mass of the compound. So using the molar mass formula for an element, we calculate the molar mass for each element then we sum up their molar masses to get the compounds molar mass.

Molar mass (Ca)= 1× 40

(Ca)= 40

Molar mass (Mn)=2×55

(Mn)= 110

Molar mass (O)= 8×16

(O)= 128

Now: Molar mass( compound)= (Ca)+(Mn)+(O)

= 40+ 110 128

= 278

This is everything we need to calculate our percentage composition for each element..

* The example says to find the percentage composition for Ca. So we only find for Ca, Which is already done using the formula and the answer is 14.39%.

To prove that your answer is correct, find the percentage composition for Mn and O as well. Then you add up their percentage compositions.

If you do and you get 100 as your answer, then your percentage compositions are correct.

Why don't you try finding the percentage composition for Mn and O, then add up all the three percentage compositions. If you 100 as their sum, then your percentage composition for each of the elements are correct.

6 0
2 years ago
What is the balanced equation for CaCO3(s) &gt; CaO(s) + CO2(g
vlada-n [284]
Balanced equation :

1 CaCO3(s) = 1 CaO(s) + 1 CO2(g)

hope this helps!

3 0
3 years ago
A chemical reaction that is first-order in X is observed to have a rate constant of 1.50 × 10–2 s–1. If the initial concentratio
elena-s [515]

Answer:

0.053 M is the concentration of X after 196 seconds.

Explanation:

Initial concentration of the X = [A_o]=1.0 M

Time taken by the sample, t = 196 s

Final concentration of the X after t = [A] =?

Rate constant of the reaction = k = 1.50\times 10^{-2} s^{-1}

Formula used :

[A]=[A_o]\times e^{-kt}

where,

Now put all the given values in this formula, we get

[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}

[A]=0.053 M

0.053 M is the concentration of X after 196 seconds.

3 0
3 years ago
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