Answer:
2.09 atm
Explanation:
Step 1: Given and required data
- Volume of the vessel (V): 25.0 L
We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.
Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
60.0 g × 1 mol/44.01 g = 1.36 mol
Step 3: Calculate the partial pressure of CO₂
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/ V
P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm
The correct balanced chemical equation which occur when methane burn in oxygen gas is
CH4 + 2O2 --> 2H2O +CO2 (answer D)
when methane is burned in presence of oxygen gas it produces carbon(IV) oxide and water and energy,that is 1 mole of CH4 reacted with 2 moles of O2 to form 2 moles of water and 1 mole of CO2 and enegy. This energy make the methane to be used as fuel.
Answer:
you can tell diorite is an intrusive igneous rock because it has a coarse-grained texture
The grams of Mg(OH)2 produced is calculated as below
calculate the moles of HCl produced =molarity xvolume/1000
= 0.3 x 435/1000= 0.1305 moles
write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O
by use of mole ratio between HCl :MgCl2 which is 2 :1 the moles of HCl = 0.1305 x1/2 =0.0653 moles of MgCl2
mass of MgCl2 = moles x molar mass
= 0.0653mol x95 g/mol = 6.204 grams of MgCl2
