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3 years ago

How many atoms of each element are chemical formula: 3K2O3.

Chemistry

2 answers:

hammer [34]3 years ago

4 0

Answer:

In 3K2O3 - 6 K atoms, 9 O atoms

In 2H3NCH3Br - 12 H atoms, 2 N atoms, 2 C atoms, 2 Br atoms

In 4 Ar2CO3 - 8 Ar atoms, 4 C atoms, 12 O atoms

Explanation:

All you need to do is multiply the coefficient by the number of each atom in the compound. For example, H3NCH3Br has 1 nitrogen, 1 carbon, 1 bromine, and 6 hydrogens. If you have 2H3NCH3Br, just multiply all those numbers by 2.

aksik [14]3 years ago

4 0

3k2o3 = 15

2h3nch3br = 17

4ar2co3 = 24

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How many grams of Br are in 335g of CaBr2

ASHA 777 [7]

The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g

7 0

3 years ago

12.2 scientific notation

Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

3 0

3 years ago

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Alex17521 [72]

<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 91.2321 \ g \ Mn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0

3 years ago

Read 2 more answers

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Nookie1986 [14]

There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

5. Rubidium

6. Francium

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3 years ago

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I am Lyosha [343]

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Explanation:

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3 years ago