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Fynjy0 [20]
3 years ago
7

The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x + 7. The

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0
<h3>The value of x is 4.10</h3>

<em><u>Solution:</u></em>

Given that,

The angle Johnny holds his pen on paper creates a linear pair

Angles in a linear pair are supplementary angles

Two angles are supplementary, when they add up to 180 degrees

The measure of one angle is 13x + 7

The  measure of the second angle is one less than twice the first angle

Therefore,

Measure of second angle = twice the first angle - 1

Measure of second angle = 2(13x + 7) - 1

Measure of second angle = 26x + 14 - 1

Measure of second angle = 26x + 13

Therefore,

Measure of first angle + measure of second angle = 180

13x + 7 + 26x + 13 = 180

39x + 20 = 180

39x = 180 - 20

39x = 160

x = 4.1

Thus value of x is 4.10

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f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

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P(X \leq 1) = P(X=1) =0.6923

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Step-by-step explanation:

For this case we have the following density function:

f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

P(X \leq 1) = P(X=1) =0.6923

P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077

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